We have a free fall problem where a ball is dropped from 50 meters high. The ball starts with zero initial velocity and falls under the influence of gravity, which is 9.8 meters per second squared. We need to find the final velocity when it reaches the ground.
To solve this problem, we use the kinematic equation v squared equals v naught squared plus 2gh. Since the initial velocity is zero, the height is 50 meters, and gravity is 9.8 meters per second squared, we get v squared equals 980. Taking the square root gives us a final velocity of 31.3 meters per second.
Now let's watch the ball fall in real time. As the ball drops from 50 meters, its velocity continuously increases due to gravitational acceleration. The velocity arrow grows longer as the ball falls faster, reaching the final velocity of 31.3 meters per second when it hits the ground.
The velocity versus time graph for free fall is a straight line starting from zero. The slope of this line equals the gravitational acceleration of 9.8 meters per second squared. After 3.19 seconds of falling, the ball reaches its final velocity of 31.3 meters per second, which matches our calculated result.
In conclusion, we have successfully solved the free fall problem. A ball dropped from 50 meters height reaches a final velocity of 31.3 meters per second when it hits the ground. This result was obtained using the kinematic equation v squared equals v naught squared plus 2gh, with zero initial velocity and gravitational acceleration of 9.8 meters per second squared.