尝试解答---The extracted content from the image is as follows:
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**Question 6**
**Question Stem:**
用系统命名法命名下面的烃：
其一氯代物有 ______ 种。
**Translation of Question Stem:**
Name the following hydrocarbon using systematic nomenclature:
Its monochloro-substitution products have ______ types.
**Chemical Structure Description:**
The image displays a skeletal/condensed structural formula of a branched alkane.
The structure can be interpreted as:
```
CH3
|
CH3 - C - CH2 - CH - CH2 - CH3
| |
CH2CH3 CH2CH3
```
This represents the molecule 3-ethyl-5-methylheptane.
**Analysis for Answering the Question (not part of extraction, but for completeness of understanding):**
1. **Systematic Nomenclature (IUPAC Name):**
* Identify the longest continuous carbon chain. In this case, starting from the CH3 of one of the ethyl groups and going through the main chain, there is a 7-carbon chain: `CH3-CH2-C(CH3)-CH2-CH(CH2CH3)-CH2-CH3`. This is a heptane.
* Number the chain to give the lowest possible locants to the substituents.
* If numbered from left to right (starting from CH3 of the C2-ethyl group):
`C1-C2-C3(CH3)-C4-C5(CH2CH3)-C6-C7`
Substituents: methyl at C3, ethyl at C5. Locants: 3, 5.
* If numbered from right to left (starting from the terminal CH3):
`C7-C6-C5(CH3)-C4-C3(CH2CH3)-C2-C1`
Substituents: ethyl at C3, methyl at C5. Locants: 3, 5.
* Both numberings give the same locants. Alphabetical order for substituents: ethyl before methyl.
* Therefore, the systematic name is **3-ethyl-5-methylheptane**.
2. **Number of Monochloro-substitution Products:**
To determine the number of monochloro-substitution products, we need to count the number of non-equivalent hydrogen atoms in the molecule. Replacing any one of these unique hydrogens with a chlorine atom will result in a distinct structural isomer.
The structure of 3-ethyl-5-methylheptane:
```
CH3 (at C5)
|
CH3(C7) - CH2(C6) - CH(C5) - CH2(C4) - CH(C3) - CH2(C2) - CH3(C1)
|
CH2CH3 (at C3)
```
Let's identify the unique hydrogen environments (numbering from C1 on the right to C7 on the left):
* **H on C1 (CH3):** All 3 hydrogens are equivalent. (1 unique position)
* **H on C2 (CH2):** All 2 hydrogens are equivalent. (1 unique position)
* **H on C3 (CH):** The single hydrogen is unique. (1 unique position)
* **H on CH2 of ethyl group (at C3):** All 2 hydrogens are equivalent. (1 unique position)
* **H on CH3 of ethyl group (at C3):** All 3 hydrogens are equivalent. (1 unique position)
* **H on C4 (CH2):** All 2 hydrogens are equivalent. (1 unique position)
* **H on C5 (CH):** The single hydrogen is unique. (1 unique position)
* **H on CH3 of methyl group (at C5):** All 3 hydrogens are equivalent. (1 unique position)
* **H on C6 (CH2):** All 2 hydrogens are equivalent. (1 unique position)
* **H on C7 (CH3):** All 3 hydrogens are equivalent. (1 unique position)
No two of these positions are chemically equivalent due to the lack of symmetry in the molecule.
Therefore, there are **10** distinct types of hydrogen atoms.
**Answer to the fill-in-the-blank for Question 6:**
10
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**Question 10 (Incomplete)**
**Other Relevant Text:**
10.「辽宁名校联盟 2024 高一联考改编] 为探究
**Translation of Other Relevant Text:**
10. [Adapted from Liaoning Famous Schools Alliance 2024 Grade 1 Joint Examination] To explore
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