解题---**Question 7:** **Question Stem:** 7. 下列有机反应方程式书写正确的是 (Which of the following organic reaction equations is correctly written?) **Options:** A. 乙烯与溴水反应: CH₂=CH₂ + Br₂ → CH₃CHBr₂ B. 乙醇的催化氧化: CH₃CH₂OH + 3O₂ $\xrightarrow{催化剂}{\triangle}$ 2CO₂ + 3H₂O C. 苯的硝化反应: [Benzene Ring] + HNO₃ $\xrightarrow{浓硫酸}{\triangle}$ [Nitrobenzene Ring] + H₂O D. 乙酸与乙醇发生酯化反应: CH₃COOH + CH₃CH₂¹⁸OH $\xrightarrow{浓硫酸}{加热}$ CH₃COOCH₂CH₃ + H₂¹⁸O **Chart/Diagram Description:** The image displays a multiple-choice question (Question 7) related to organic chemistry reactions. Each option presents an organic reaction with its reactants, products, and reaction conditions. * **Option A:** Shows the reaction of ethene (CH₂=CH₂) with bromine (Br₂). The product is shown as CH₃CHBr₂. There is a handwritten red note "溴水" (Bromine water) next to the product. * **Option B:** Shows the catalytic oxidation of ethanol (CH₃CH₂OH) with oxygen (O₂), yielding carbon dioxide (CO₂) and water (H₂O). The reaction conditions indicated are "催化剂" (catalyst) and "△" (heat). * **Option C:** Shows the nitration of benzene. The reactant is a benzene ring (represented as a hexagon with an inner circle) reacting with nitric acid (HNO₃). The product shown is a nitrobenzene ring (a hexagon with an inner circle and an -NO₂ group attached to one vertex) and water (H₂O). The reaction conditions are "浓硫酸" (concentrated sulfuric acid) and "△" (heat). A checkmark is present next to option C, indicating it is the selected answer. * **Option D:** Shows the esterification reaction between acetic acid (CH₃COOH) and ethanol (CH₃CH₂¹⁸OH), where the oxygen in ethanol is an isotope ¹⁸O. The products are shown as ethyl acetate (CH₃COOCH₂CH₃) and water containing the ¹⁸O isotope (H₂¹⁸O). The reaction conditions are "浓硫酸" (concentrated sulfuric acid) and "加热" (heating).