生成这个题目的讲解---**Extracted Content:** **Question Stem:** 如图, 矩形ABCD的对角线AC, BD相交于点O. 若∠AOB=60°, 则AB/BC = ( ) *Translation:* As shown in the figure, the diagonals AC and BD of rectangle ABCD intersect at point O. If ∠AOB = 60°, then AB/BC = ( ) **Options:** A. 1/2 B. (√3 - 1)/2 C. √3/2 D. √3/3 **Other Relevant Text (Hint/Partial Solution):** 先证△ABO是等边三角形, 可得∠BAO=60°, 由直角三角形的性质可求解. *Translation:* First prove that △ABO is an equilateral triangle, then we can get ∠BAO=60°, and the problem can be solved using properties of right-angled triangles. **Chart/Diagram Description:** * **Type:** Geometric figure. * **Main Elements:** * **Shapes:** A rectangle named ABCD. * **Lines:** Two diagonals, AC and BD, drawn inside the rectangle. * **Points:** * The four vertices of the rectangle: A (top-left), B (bottom-left), C (bottom-right), D (top-right). * The intersection point of the diagonals: O, located in the center of the rectangle. * **Relative Position and Direction:** The diagonals AC and BD intersect at point O. Point O is centrally located within the rectangle.