请根据这个图片帮我制作一个讲解初中几何《角平分线+飞镖模型》，标题就叫：角平分线+飞镖模型---**Overall Title:** 模型三 “角平分线+飞镖”模型 (Model 3 "Angle Bisector + Dart" Model) --- **Section 1: 内内飞镖 (Inner Dart)** **Chart/Diagram Description:** * **Type:** Geometric figure (Triangle with an internal point). * **Main Elements:** * **Shapes:** A large triangle labeled ABC. Inside this triangle, there is an internal point P. * **Lines:** Straight line segments form the sides of triangle ABC (AB, BC, CA). Straight line segments connect point P to vertices B and C (BP, CP). * **Points:** Labeled vertices A, B, C. Labeled internal point P. * **Relative Position:** Point P is located inside triangle ABC. **Textual Information (Problem Statement/Condition):** BP、CP 分别是 ∠ABC 和 ∠ACB 的角平分线，则：∠P = 90° + 1/2 ∠A (Translation: BP and CP are the angle bisectors of ∠ABC and ∠ACB respectively, then: ∠P = 90° + 1/2 ∠A) --- **Section 2: 证明 (Proof)** **Textual Information (Proof Steps):** 根据飞镖模型的结论可知： (Translation: According to the conclusion of the dart model, it is known that:) ∠P = ∠A + ∠ABP + ∠ACP ∵ BP、CP 分别是 ∠ABC 和 ∠ACB 的角平分线 (Translation: ∵ BP and CP are the angle bisectors of ∠ABC and ∠ACB respectively) ∴ ∠ABP + ∠ACP = 1/2 (∠ABC + ∠ACB) = 1/2 (180° - ∠A) ∴ ∠P = 90° + 1/2 ∠A