请把图中第5道题至第8道题,分别进行讲解---Here is the extracted content from the image:
**Question 5:**
**Question Stem:**
用配方法解方程 $x^2 - 4x + 1 = 0$ 时,结果正确的是 ( )
**Options:**
A. $(x-2)^2 = 5$
B. $(x-2)^2 = 3$
C. $(x+2)^2 = 5$
D. $(x+2)^2 = 3$
**Mathematical Formulas:**
$x^2 - 4x + 1 = 0$
$(x-2)^2 = 5$
$(x-2)^2 = 3$
$(x+2)^2 = 5$
$(x+2)^2 = 3$
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**Question 6:**
**Question Stem:**
二次函数 $y = ax^2 + bx + c$ 的 $x$ 与 $y$ 的部分对应值如下表: 则 $m$ 的值是 ( )
**Options:**
A. 1
B. 2
C. 5
D. 10
**Mathematical Formulas:**
$y = ax^2 + bx + c$
**Table:**
| x | -1 | 0 | 1 | 2 | 3 | 4 |
|---|---|---|---|---|---|---|
| y | m | 2 | 1 | 2 | 5 | 10 |
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**Question 7:**
**Question Stem:**
如图, 在 $\triangle ABC$ 中, $\angle BAC = 135^\circ$, 将 $\triangle ABC$ 绕点 $C$ 逆时针旋转得到 $\triangle DEC$, 点 $A,B$ 的对应点分别为 $D,E$, 连接 $AD$. 当点 $A,D,E$ 在同一条直线上时, 下列结论不正确的是 ( )
**Options:**
A. $\triangle ABC \cong \triangle DEC$
B. $\angle ADC = 45^\circ$
C. $AD = \sqrt{2} AC$
D. $AE = AB + CD$
**Mathematical Formulas:**
$\angle BAC = 135^\circ$
$AD = \sqrt{2} AC$
**Chart/Diagram Description:**
Type: Geometric figure illustrating triangles and points.
Main Elements:
- Points: Labeled points A, B, C, D, E.
- Shapes: Two triangles, $\triangle ABC$ and $\triangle CDE$.
- Lines: Line segments AC, BC, AB, CD, CE, DE, AD, AE.
- Angles: Angle $\angle BAC$ is indicated as $135^\circ$. Point C is the center of rotation. Points A, D, E lie on a straight line.
- Relationships: $\triangle DEC$ is obtained by rotating $\triangle ABC$ counterclockwise around point C. Points A and D are corresponding points, B and E are corresponding points. AD is connected. A, D, E are collinear.
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**Question 8:**
**Question Stem:**
如图, 已知关于 $x$ 的一元二次方程 $a(x-k)^2 - 1 = 0$ 的两根在数轴上对应的点分别在区域①和区域②, 区域均含端点, 则 $k$ 的值可能是 ( )
**Options:**
A. -1
B. 0
C. 1
D. 2
**Mathematical Formulas:**
$a(x-k)^2 - 1 = 0$
**Chart/Diagram Description:**
Type: Number line.
Main Elements:
- Axis: Horizontal line with an arrow to the right, labeled with integers from -2 to 3.
- Labels: Numbers -2, -1, 0, 1, 2, 3 are marked below the line.
- Regions: Two regions are marked above the line.
- Region ①: Indicated above the interval from -1 to 0, labeled with ①. This region includes the endpoints -1 and 0, represented by square brackets implicitly.
- Region ②: Indicated above the interval from 2 to 3, labeled with ②. This region includes the endpoints 2 and 3, represented by square brackets implicitly.
- Description: The two roots of the equation are located one in region ① and one in region ②. Regions include their endpoints.