帮我解一下图里这道数学题---**Problem Number:** 19 **Points:** 8 points **Question Stem:** 如图, 在△ABC 中, CE ⊥ AB 于点 E, 点 D 在 BC 上, 连接 AD 交 CE 于点 F, BC = 13, CE = 12. As shown in the figure, in △ABC, CE ⊥ AB at point E, point D is on BC, AD intersects CE at point F, BC = 13, CE = 12. **(1)** 求 BE 的长; Find the length of BE; **(2)** 若 ∠AFE = 45°, AB = CF, 求 AE 的长. If ∠AFE = 45°, AB = CF, find the length of AE. **Diagram Description:** * **Type:** Geometric figure (Triangle). * **Main Elements:** * A triangle ABC is shown. * Point E is on side AB. * Line segment CE is drawn from C to E, and it is perpendicular to AB at E (indicated by a right angle symbol at E). * Point D is on side BC. * Line segment AD is drawn from A to D, intersecting CE at point F. * Points are labeled A, B, C, D, E, F. * The intersection point of AD and CE is labeled F. * **Relative Position and Direction:** * CE is perpendicular to AB at E. * D is on BC. * AD intersects CE at F. * **Labels and Annotations:** * Vertices A, B, C are labeled. * Points E, D, F are labeled. * A right angle symbol is shown at E, indicating CE ⊥ AB. * The text "(第 19 题)" is below the diagram, indicating "Question 19".