Let's solve a classic probability problem. We have a bag containing 5 red marbles and 3 blue marbles. We want to find the probability of drawing 2 red marbles without replacement.
Let's solve this step by step. For the first draw, we have 8 total marbles: 5 red and 3 blue. The probability of drawing a red marble first is 5 out of 8, or five-eighths.
For the second draw, we now have only 7 marbles left since we removed one red marble. There are 4 red marbles remaining out of 7 total. So the probability of drawing a second red marble is 4 out of 7, or four-sevenths.
Now we calculate the final probability by multiplying the two individual probabilities. Five-eighths times four-sevenths equals twenty fifty-sixths, which simplifies to five-fourteenths. This is our final answer.