There is a ball that is thrown at a 50 degree angle traveling 47 centimeters a second. Every time the ball bounces, the ball regains 87% of it height. How far and high is the ball from it original start, x, after 10 seconds
视频信息
答案文本
视频字幕
We have a projectile motion problem with a bouncing ball. The ball is thrown at a 50-degree angle with an initial velocity of 47 centimeters per second. Each time the ball bounces, it retains 87% of its height. We need to find the ball's position after 10 seconds.
First, we need to break down the initial velocity into horizontal and vertical components. The horizontal component is 47 times cosine of 50 degrees, which equals 30.21 centimeters per second. The vertical component is 47 times sine of 50 degrees, which equals 35.95 centimeters per second. The horizontal velocity remains constant throughout the motion, while the vertical velocity changes due to gravity.