求解这道题目---**Question:** 23. (2021 黑龙江哈尔滨中考, 7, ★☆☆) 如图, △ABC ≌ △DEC, A 和 D 是对应顶点, B 和 E 是对应顶点, 过点 A 作 AF ⊥ CD, 垂足为点 F, 若 ∠BCE = 65°, 则 ∠CAF 的度数为 ( ) **Options:** A. 30° B. 25° C. 35° D. 65° **Chart/Diagram Description:** * **Type:** Geometric figure consisting of two triangles and a line segment. * **Main Elements:** * **Points:** Points A, B, C, D, E, and F are labeled. * **Lines:** Line segments connect points to form triangle ABC and triangle DEC. Point C is a common vertex for both triangles. A line segment connects points B and E. A line segment is drawn from A to F, where F is on the line segment CD. * **Shapes:** Triangles ABC and DEC are depicted. * **Angles:** Angle BCE is shown. Angle AFC appears to be a right angle (consistent with AF ⊥ CD). Angles within the triangles are implied. * **Labels and Annotations:** All vertices and the foot of the perpendicular are labeled with letters A, B, C, D, E, F. * **Relative Position and Direction:** Triangle ABC and triangle DEC share vertex C. Points C, F, and D appear collinear. Point F lies on the line segment CD. The line segment AF is drawn from A to F, and is perpendicular to the line containing C and D. Triangle ABC is positioned to the upper left of C, and triangle DEC is positioned to the upper right of C. **Other Relevant Text:** Source: 2021 黑龙江哈尔滨中考, 7, ★☆☆ Condition: △ABC ≌ △DEC, A and D are corresponding vertices, B and E are corresponding vertices, AF ⊥ CD, foot of the perpendicular is F, ∠BCE = 65°. Requested value: ∠CAF.