Crear un video con la solución al siguiente problema: Un camión recorre 40.0 m en 8.50 s mientras disminuye su velocidad de manera uniforme a una velocidad final de 2.80 m/s. a) Encuentre la rapidez original del
camión. b) Determine su aceleración
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Let's solve this kinematics problem step by step. We have a truck that travels 40 meters in 8.5 seconds while uniformly decreasing its speed to a final velocity of 2.8 meters per second. We need to find the original speed and the acceleration.
Let's organize our given information and identify what we need to find. We know the distance is 40 meters, the time is 8.5 seconds, and the final velocity is 2.8 meters per second. We need to find the original velocity and the acceleration of the truck.
Now let's find the original velocity. We'll use the kinematic equation that relates distance, time, initial velocity, and final velocity. The equation is d equals the average of initial and final velocity times time. Substituting our values: 40 equals vi plus 2.8 divided by 2, times 8.5. Solving step by step, we get vi equals 6.61 meters per second.
Now let's find the acceleration using the equation vf equals vi plus a times t. Substituting our known values: 2.80 equals 6.61 plus a times 8.50. Solving for acceleration: a times 8.50 equals negative 3.81, so a equals negative 0.448 meters per second squared. The negative sign indicates the truck is decelerating.
Let's summarize our solution. We found that the original speed of the truck was 6.61 meters per second, and the acceleration was negative 0.448 meters per second squared. The negative acceleration confirms that the truck was decelerating uniformly as it traveled the 40 meters in 8.5 seconds, slowing down from 6.61 to 2.80 meters per second.