如图, 已知四边形 ABCD, AC, BD 为对角线, 其中 AB=AC=AD, △ABC 的外接圆交 AD 边于点 E, 连接 BE, CE, 若 BC=2, BE=3, BD=4, 则 △CDE 的外接圆面积为多少？---**Problem Description:** 9. 如图, 已知四边形 ABCD, AC, BD 为对角线, 其中 AB=AC=AD, △ABC 的外接圆交 AD 边于点 E, 连接 BE, CE, 若 BC=2, BE=3, BD=4, 则 △CDE 的外接圆面积为 **Translation of Problem Description:** 9. As shown in the figure, given quadrilateral ABCD, AC and BD are diagonals, where AB=AC=AD. The circumscribed circle of △ABC intersects side AD at point E. Connect BE, CE. If BC=2, BE=3, BD=4, then the area of the circumscribed circle of △CDE is **Options:** A. $\frac{9}{4}\pi$ B. $\frac{16}{9}\pi$ C. $\frac{25}{16}\pi$ D. $\frac{36}{25}\pi$ **Diagram Description:** * **Type:** Geometric figure involving a circle and a quadrilateral. * **Elements:** * A circle is present. * Points A, B, C, E are on the circle. * Point D is outside the circle. * Quadrilateral ABCD is shown, with diagonals AC and BD. * Lines connecting points are shown: AB, BC, CD, DA, AC, BD, BE, CE. * The circumscribed circle of △ABC passes through points A, B, and C. * Point E is on the circle and on the line segment AD. * Lines BE and CE are drawn. * **Labels:** Points are labeled A, B, C, D, E. * **Other Text:** "第 9 题图" (Figure for question 9) is written below the diagram.