如图，直线AB、CD相交于点O，∠DOF = 90°，OF平分∠AOE，若∠BOD = 32°，则∠EOF的度数为( ) A．32° B．48° C．58° D．64°---**Chart/Diagram Description:** * **Type:** Geometric diagram. * **Main Elements:** * **Lines:** Two intersecting straight lines, labeled AB and CD. * **Points:** The intersection point of lines AB and CD is labeled O. Points A, O, and B are collinear. Points C, O, and D are collinear. Four additional rays originate from O, labeled OE and OF. * **Rays:** Ray OA and ray OB form the line AB. Ray OC and ray OD form the line CD. Ray OE originates from O. Ray OF originates from O. Ray OF is located in the angle COA. Ray OE is located in the angle DOF. Specifically, ray OF is roughly between OA and OC. Ray OE is roughly between OF and OD. * **Angles:** Various angles are formed by the intersecting lines and rays, such as ∠AOC, ∠COB, ∠BOD, ∠DOA, ∠AOF, ∠COF, ∠COE, ∠DOE, ∠EOF, ∠AOD, ∠COB. ∠AOC and ∠BOD are vertically opposite angles. ∠COB and ∠AOD are vertically opposite angles. ∠AOC + ∠COB = 180° (straight angle). * **Relative Position:** Line AB is horizontal. Line CD is an oblique line intersecting AB at O. Ray OF and ray OE are in the upper half-plane formed by line AB. Ray OF is to the left of line CD, and ray OE is to the right of line CD, or both are in the upper region relative to line AB. Based on the arrangement, ray OF is in the region between OA and OC. Ray OE is in the region between OF and OD. **Extraction Content:** Based solely on the image provided, there is no question stem, options, or other textual content to extract. The image contains only a geometric diagram.