如图，直线AB、CD交于点O，OE平分∠BOD，∠AOC = 66°。（1）求∠EOD的度数；（2）画射线OF，使OF⊥CD，求∠EOF的度数。---**Chart/Diagram Description:** * **Type:** Geometric diagram showing intersecting lines and a ray. * **Main Elements:** * **Points:** Points labeled are O (the intersection point), A, B, C, D (points on the lines/rays), and E (a point on a ray originating from O). * **Lines:** * A line passing through points C, O, and A. * A line passing through points B, O, and D. * A ray originating from point O and passing through point E. * **Shapes:** Angles formed by the intersecting lines and ray. These include ∠AOB, ∠BOC, ∠COD, ∠DOA, ∠BOE, ∠DOE, ∠COE, ∠AOE. * **Coordinate Axes:** Not present. * **Labels and Annotations:** Points are labeled A, B, C, D, O, E. * **Relative Position and Direction:** Lines AC and BD intersect at O. Ray OE originates from O. In the diagram, ray OE appears horizontal, ray OB is above OE and to the right, ray OD is below OE and to the right, ray OC is above and to the left of O, and ray OA is below and to the left of O. Points A, O, C are collinear. Points B, O, D are collinear. **Textual Information:** * **Question Stem:** (No question stem is present in the image.) * **Options:** (No options are present in the image.) * **Other Relevant Text:** (No other relevant text is present in the image.) * **Mathematical Formulas/Chemical Equations:** (No mathematical formulas or chemical equations are present in the image.) * **Table Content:** (No table content is present in the image.)