解答这一题---Question Number: 10. (1分) Question Stem: 将如图的展开图围成正方体后，“海”的对面是“_________”。 Diagram Description: Type: Cube net diagram. Main Elements: - Six squares arranged in a 2-3-1 configuration (two in the first column, three in the second column, one in the third column, but specifically, the second column has three squares stacked vertically, with the first column square attached to the middle square of the second column, and the third column square attached to the top square of the second column). - Each square contains a Chinese character. - The arrangement of squares is as follows: - Top row: Empty | "学" | "海" - Middle row: "无" | "涯" | Empty - Bottom row: "勤" | "思" | Empty - Note: The image shows the net rotated or arranged differently. Let's describe it row by row from top to bottom as shown: - Row 1: Empty (implied blank space) | "学" | "海" - Row 2: "无" | "涯" | Empty (implied blank space) - Row 3: "勤" | "思" | Empty (implied blank space) - Let's describe it based on relative positions as shown in the image: - Square "学" is to the left of "海". - Square "无" is below "学". - Square "涯" is to the right of "无" and below "海". - Square "勤" is below "无". - Square "思" is to the right of "勤" and below "涯". More standard description of the net based on common types: This net is a type where there is a row of four squares, with one square above and one square below one of the squares in the row of four. In this image, it's presented somewhat like a stepped structure. Let's analyze the connectivity: "学" is connected to "海" on its right. "学" is connected to "无" below it. "海" is connected to "涯" below it. "无" is connected to "勤" below it and "涯" to its right. "涯" is connected to "无" on its left and "思" below it. "勤" is connected to "无" above it. "思" is connected to "涯" above it. Let's re-orient mentally to a typical row of four: Imagine "勤", "无", "学", "海" are in a line horizontally. Then "涯" would be attached below "学" and "思" below "涯". This doesn't match the image. Let's use the columns as presented: Column 1 (left): "勤" (bottom), "无" (middle) Column 2 (middle): "思" (bottom), "涯" (middle), "学" (top) Column 3 (right): "海" (top) Connectivity based on the image: "勤" is connected to "无" above it and "思" to its right. "无" is connected to "勤" below it, "学" above it, and "涯" to its right. "学" is connected to "无" below it and "海" to its right. "思" is connected to "勤" on its left and "涯" above it. "涯" is connected to "无" on its left, "思" below it, and "海" above it. (Error in this connectivity - 海 is to the right of 学, not above 涯). Let's try to represent the net layout more clearly: The bottom row is "勤" and "思". Above "勤" is "无". Above "无" is "学". To the right of "学" is "海". To the right of "无" is "涯". To the right of "思" is nothing shown in the image. Let's visualize folding. If "勤" is the base, "无" and "思" are adjacent sides. If "无" is folded up, "学" is connected above "无". "涯" is connected to the side of "无". "海" is connected to the side of "学". "思" is connected to the side of "涯". Alternatively, let's use the rule that in a linear arrangement of squares in a net, alternating squares are opposite faces. Consider the sequence "勤" - "无" - "学" - "海". If these were in a straight line, "勤" would be opposite "学", and "无" would be opposite "海". However, they are not in a straight line. Consider the "3+1+1+1" pattern (three consecutive squares in a line, and one attached to the first, one to the second, one to the third). In this case, let's consider the row "无" - "涯". "学" is above "无", "勤" is below "无", "海" is to the right of "学", "思" is below "涯". Consider "无", "涯" as part of a line. "学" is above "无", "勤" is below "无". "海" is to the right of "学", "思" is below "涯". Let's look for parallel edges that become opposite faces. If we fold the net: "勤" and "学" are separated by "无". So "勤" is opposite "学". "无" and "海" are separated by "学". So "无" is opposite "海". "思" and "涯" are adjacent. Let's check the remaining two faces. The faces are "勤", "无", "学", "海", "涯", "思". Pairs of opposite faces are: (勤, 学), (无, 海), (涯, 思). Let's verify this by mentally folding. If "无" is the front face, "学" is above it, "勤" is below it. "涯" is to the right of "无". If we fold "涯" up to be the right face, then "思" is below "涯", so "思" is the bottom face. "海" is to the right of "学". If "学" is the top face, then "海" is the right face. This conflicts with "涯" being the right face. Let's re-examine the pairs: (勤, 学), (无, 海), (涯, 思). If we use the rule that faces separated by one face in a straight line are opposite, then "无" is opposite "海" (separated by "学"), "勤" is opposite "学" (separated by "无"). This leaves "涯" and "思" as opposite. Let's test this set of pairs. If "学" is the top face, then "勤" is the bottom face. "无" is connected to "学" below it, so "无" is a side face (say, front). "海" is connected to "学" on its left, so "海" is another side face (say, right). If "无" is front, "海" is right, and "学" is top, then "涯" is connected to the right of "无". So "涯" is the right face. This again conflicts. Let's assume the row "无", "涯", "思" is in a line. This is not how it is arranged. Let's consider the column "学", "无", "勤". If "无" is the center, then "学" and "勤" are separated by "无". If these three were in a straight line, "学" and "勤" would be opposite. But they are not in a straight line forming a row of four. Let's consider the arrangement as a base and sides. If "涯" is the base, then "无" is above it, "思" is below it. "学" is above "无". "勤" is below "无". "海" is to the right of "学". "思" is to the right of "勤". Let's use the rule for common cube nets. In a "+" shaped net, opposite faces are the middle square and the top/bottom square, and the left/right squares are opposite. This is not a "+" shape. In a row of four squares with one above and one below, the two squares not in the row are opposite each other. The first and third, and second and fourth in the row of four are opposite. Let's go back to the pairs (勤, 学), (无, 海), (涯, 思). If "无" is opposite "海", then folding "学" up and "涯" to the side, and "勤" down, and "思" to the side should form a cube. Let's pick a face, say "无", as the front. "学" is above "无" (top). "勤" is below "无" (bottom). "涯" is to the right of "无" (right). Then "海" is to the right of "学". If "学" is top, and "涯" is right, then "海" is connected to the side of the top face. If we fold the top face ("学") and the right face ("涯"), "海" is connected to the side of "学". This side of "学" is adjacent to "涯". Let's rethink the pairs using adjacency. Adjacent faces share an edge. Opposite faces share no points. "海" is adjacent to "学" and "涯". So "海" is not opposite "学" or "涯". "学" is adjacent to "无" and "海". So "学" is not opposite "无" or "海". "无" is adjacent to "学", "勤", and "涯". So "无" is not opposite "学", "勤", or "涯". "涯" is adjacent to "无", "海", and "思". So "涯" is not opposite "无", "海", or "思". "勤" is adjacent to "无" and "思". So "勤" is not opposite "无" or "思". "思" is adjacent to "勤" and "涯". So "思" is not opposite "勤" or "涯". We need to find the face opposite to "海". "海" is adjacent to "学" and "涯". Let's try folding again. Let "无" be the front face. "学" is the top face. "勤" is the bottom face. "涯" is the right face. "思" is below "涯", so it's the bottom face (conflicts with "勤" being bottom). So this assignment of base is incorrect. Let's try a different approach. Imagine "学", "无", "勤" as being in a column. Then "海" is to the right of "学", "涯" is to the right of "无", "思" is to the right of "勤". This arrangement (3x1 column with a column of 1x3 attached to the right) is not a valid cube net. The arrangement is: 学 海 无 涯 勤 思 Let's visualize the folding process. If "无" is the front face, "学" is the top, "勤" is the bottom. Then "涯" is to the right of "无". So "涯" is the right face. "海" is to the right of "学". If "学" is the top, the face to its right when folding up is "涯". This again leads to issues. Let's assume the standard rule for nets where squares separated by one square in a line are opposite. Consider the row "学" - "无" - "勤" and "海" - "涯" - "思". These are not linear rows in the net. Consider the path "海" - "学" - "无" - "勤". "海" and "无" are separated by "学". "海" and "勤" are separated by "学" and "无". Let's look at the net again. 学 海 无 涯 勤 思 Imagine "无" as the base. Then "学" folds up to be a side, and "勤" folds down to be a side. This doesn't work. Let's assume "无" is the front. "涯" is the right. "学" is the top. "海" is connected to the side of "学" and "涯". When "学" is the top and "涯" is the right, the face to the right of the top face is part of the right face. The face below the top face and to the right is the right face. The face to the right of the top face that is not the right face is the back face. "海" is to the right of "学" and above "涯". If "无" is front, "涯" is right, "学" is top, then "海" is connected to the top face and right face. This means "海" is the corner connecting top, front/back, and right faces. But "海" is a face, not an edge or vertex. Let's consider the pairings again: (勤, 学), (无, 海), (涯, 思). Let's try to fold based on these pairs. If "学" is the top, "勤" is the bottom. "无" is adjacent to "学", so it's a side face (say, front). "海" is adjacent to "学", so it's a side face (say, right). "涯" is adjacent to "无". If "无" is front, "涯" can be right or left. But "涯" is also adjacent to "海". If "海" is right, and "涯" is right or left of "无", and "涯" is adjacent to "海", then "涯" must be the right face, adjacent to both "无" and "海". This contradicts "海" being the right face. Let's use the common method: choose one face as the base, then identify adjacent and opposite faces by folding. Let's pick "无" as the front face. "学" is above "无", so "学" is the top face. "勤" is below "无", so "勤" is the bottom face. "涯" is to the right of "无", so "涯" is the right face. "海" is to the right of "学". If "学" is the top, the face to its right is the right face ("涯"). But "海" and "涯" are different faces. Let's reconsider the layout. 学 海 无 涯 勤 思 Let's assume "无" is the front. Folding "学" up makes it the top face. Folding "海" up makes it the back face. Folding "勤" down makes it the bottom face. Folding "思" to the right of "勤" makes it the right face. Folding "涯" to the right of "无" makes it the right face (conflict). Let's try another base. Let "学" be the top face. Then "无" is below it (front face, for example). "海" is to the right of "学". When "学" is the top, "海" is a side face. Which side? Let's look at the connections. "海" is connected to "学" and "涯". "学" is connected to "海" and "无". "无" is connected to "学", "勤", and "涯". "涯" is connected to "无", "海", and "思". "勤" is connected to "无" and "思". "思" is connected to "勤" and "涯". Pairs of faces that are opposite share no common adjacent faces. Adjacent faces of "海" are "学" and "涯". Faces not adjacent to "海": "无", "勤", "思". One of these is opposite to "海". "无" is adjacent to "学" and "涯". So "无" is adjacent to faces that are adjacent to "海". This doesn't directly tell us about opposite faces. Let's revisit the (勤, 学), (无, 海), (涯, 思) pairing. Let's try to confirm this pairing using the rule about '隔一个' (separated by one). Consider the path "海" - "学" - "无". "海" is separated from "无" by "学". This suggests "海" and "无" are opposite. Let's see if the other pairs fit. Path "学" - "无" - "勤". "学" is separated from "勤" by "无". This suggests "学" and "勤" are opposite. Remaining pair is "涯" and "思". So the proposed pairs of opposite faces are: (学, 勤) (无, 海) (涯, 思) Let's visualize folding with these pairs. If "学" is top, "勤" is bottom. If "无" is front, "海" is back. If "涯" is right, "思" is left. Let's check adjacencies in the net: "学" is adjacent to "海" and "无". In the cube, Top is adjacent to Back, Front, Left, Right. If "学" is Top, "海" is Back, "无" is Front, then Top is adjacent to Back and Front, which works. "海" is adjacent to "学" and "涯". In the cube, Back is adjacent to Top, Bottom, Left, Right. If "海" is Back, "学" is Top, "涯" is Right, then Back is adjacent to Top and Right, which works. "无" is adjacent to "学", "勤", and "涯". In the cube, Front is adjacent to Top, Bottom, Left, Right. If "无" is Front, "学" is Top, "勤" is Bottom, "涯" is Right, then Front is adjacent to Top, Bottom, Right, which works. "涯" is adjacent to "无", "海", and "思". In the cube, Right is adjacent to Top, Bottom, Front, Back. If "涯" is Right, "无" is Front, "海" is Back, "思" is Left, then Right is adjacent to Front, Back, Left. This does not match. "涯" should be adjacent to Front, Back, Top, Bottom. Let's reconsider the pairs from the rule "隔一个". In a chain of squares, alternating squares are opposite. Chain 1: "海" - "学" - "无" - "勤". Here "海" is opposite "无", and "学" is opposite "勤". Chain 2: "海" - "涯" - "思". Here "海" is opposite "思", and "涯" is opposite nothing in this chain. Let's look at the net again and identify the connections. "学" connects "无" and "海". "无" connects "学", "勤", "涯". "涯" connects "无", "海", "思". "勤" connects "无", "思". "思" connects "勤", "涯". Opposite faces share no common adjacent face. Adjacent faces of "海" are "学", "涯". Adjacent faces of "学" are "海", "无". Adjacent faces of "无" are "学", "勤", "涯". Adjacent faces of "涯" are "无", "海", "思". Adjacent faces of "勤" are "无", "思". Adjacent faces of "思" are "勤", "涯". Let's check the proposed opposite pairs: (学, 勤), (无, 海), (涯, 思). Is "学" opposite to "勤"? Adjacent faces of "学" are "海", "无". Adjacent faces of "勤" are "无", "思". They share "无" as an adjacent face. If two faces are opposite, all faces adjacent to one must be adjacent to the other? No. Let's go back to the rule: in a straight line of squares, alternating ones are opposite. The net can be seen as: A column of "勤", "无", "学" with "思" attached to "勤" and "涯" attached to "无" and "海" attached to "学". 勤 思 无 涯 学 海 If "无" is the front face, "涯" is the right face. Then "学" is the top face, and "海" is connected to the top face and right face, so "海" is part of the back or side face. Let's use a different interpretation of the rule. Pick a face. Its opposite face is the one it is separated from by one face in a line, or the one that is 'at the other end' when folding. Consider the row formed by "无", "涯", "思". No, this is not a row. Consider the row formed by "勤", "无", "学". No, this is a column. Let's look at "海". It is connected to "学" and "涯". Let's consider the linear sequence "学" - "无" - "勤". In this column, "学" is separated from "勤" by "无". Let's consider the sequence "海" - "涯" - "思". Not a straight line. Consider the net shape again. It looks like a 'Z' shape with extensions. Let the face "无" be the front. Then "学" is on top of "无". "勤" is below "无". "涯" is to the right of "无". So "涯" is the right side. "思" is to the right of "勤". Since "勤" is the bottom, and "思" is to its right, "思" is the right side (conflict). Let's look at the standard net patterns. This net resembles a 2-3-1 pattern or a variation. Let's label the squares in rows and columns as shown in the image: Row 1: C12(学) C13(海) Row 2: C21(无) C22(涯) Row 3: C31(勤) C32(思) Connections: C12 is connected to C13 and C21. C13 is connected to C12 and C22. C21 is connected to C12, C22, C31. C22 is connected to C13, C21, C32. C31 is connected to C21 and C32. C32 is connected to C22 and C31. Let's pick a face as the base, say C21 ("无"). Then C12 ("学") and C31 ("勤") are attached above and below C21. Let's say C12 folds up to be the top, and C31 folds down to be the bottom. Then C22 ("涯") is to the right of C21 ("无"). C22 folds up to be the right face. C13 ("海") is to the right of C12 ("学"). C12 is top. The face to the right of the top is the right face. So C13 should be the right face. But C22 is also the right face. This folding is incorrect. Let's reconsider the set of opposite pairs derived from the "隔一个" rule in linear chains: (学, 勤), (无, 海), (涯, 思). Let's try to fold based on this. If "无" is the front face, then "海" is the back face. "学" is opposite "勤". "涯" is opposite "思". "无" is adjacent to "学", "勤", "涯". If "无" is front, then "学" is top or bottom or side, "勤" is one of the remaining sides, "涯" is one of the remaining sides. If "学" is top, "勤" is bottom. If "无" is front, "学" is top, "勤" is bottom. Then the remaining faces are left and right. "涯" is adjacent to "无" (front) and "学" (top). This means "涯" is either the right or left face. "海" is the back face. "海" is adjacent to "学" (top) and "涯" (right/left). If "涯" is the right face, then "海" (back) is adjacent to "学" (top) and "涯" (right). This is consistent. The remaining face is the left face, which is "思". "思" is adjacent to "勤" (bottom) and "涯" (right). This is consistent (bottom and right faces share an edge). So the opposite pairs are indeed: (学, 勤) (无, 海) (涯, 思) The question asks for the face opposite to "海". Based on our findings, the face opposite to "海" is "无". Let's check the words together: "勤学", "无涯", "思海". These are likely parts of a phrase or saying. "学海无涯勤是岸" (The sea of learning has no end, diligence is the shore). The word "思" might be related to "苦思" (deep thinking). In this context, "思" and "涯" (end) might be opposite, "勤" (diligence) and "学" (learning) are often paired. "无" (without/no) and "海" (sea) appear in the phrase "学海无涯" (the sea of learning has no end). Let's assume the pairing (无, 海) is correct based on the net folding. The question is "将如图的展开图围成正方体后，“海”的对面是“_________”。" After folding the given net into a cube, the face opposite to "海" is "_________". The diagram is: 学 海 无 涯 勤 思 Based on the standard rules for cube nets, specifically the "隔一个" rule, or by carefully visualizing the folding, we determined the opposite pairs are (学, 勤), (无, 海), and (涯, 思). Therefore, the face opposite to "海" is "无". Let's double check the net and folding. Take "无" as the front. "学" above it as top. "勤" below it as bottom. "涯" is to the right of "无", so "涯" is the right side. "海" is to the right of "学". If "学" is top, and "涯" is right, the face to the right of the top is the right side. So "海" must be the right side. This is a contradiction. Let's rethink the standard net patterns. A common net is a row of 4 with 1 above and 1 below. This net is not exactly that. Another common pattern is a 3x2 rectangle with one square removed from two opposite corners. This net is also not that. Let's use the 'column' method again. Column 1: 勤, 无 Column 2: 思, 涯, 学 Column 3: 海 Let's try to form a chain of 4: 勤-无-学-海. This chain is valid in terms of connections. 勤 is connected to 无. 无 is connected to 学. 学 is connected to 海. In this chain of 4, 勤 is opposite 学, and 无 is opposite 海. The remaining two faces are 思 and 涯. They are connected to each other and to other parts of the net. So, 思 is opposite 涯. Let's verify the connections for the chain 勤-无-学-海. 勤 is connected to 无. Yes. 无 is connected to 学. Yes. 学 is connected to 海. Yes. So the pairs of opposite faces are (勤, 学), (无, 海), (思, 涯). This matches the previous result obtained from the "隔一个" rule applied to linear segments within the net. The question asks for the face opposite to "海". According to this pairing, the face opposite to "海" is "无". Let's check if this folding works. If "无" is the front. Then "海" is the back. "学" is opposite "勤". "涯" is opposite "思". "无" is adjacent to "学", "勤", "涯". If "无" is front, "学" is adjacent, "勤" is adjacent, "涯" is adjacent. Let "学" be the top. Then "勤" is the bottom. "无" is adjacent to "学" (top), "勤" (bottom), "涯". Since "无" is front, "涯" must be a side face (left or right). "海" is the back face. "海" is adjacent to "学" (top) and "涯" (right/left). If "涯" is the right face, then the back face "海" is adjacent to the top face "学" and the right face "涯". This is correct. Then the remaining face is the left face, which is "思". "思" is opposite "涯" (right). So "思" is the left face. Let's check adjacencies of "思". "思" is adjacent to "勤" (bottom) and "涯" (right). In the cube, the left face is adjacent to the bottom face and the right face. This seems correct. So the pairings (学, 勤), (无, 海), (涯, 思) are consistent with forming a cube. The face opposite to "海" is "无". Let's write down the final extracted content. Extracted Content: Question: 10. (1分) 将如图的展开图围成正方体后，“海”的对面是“_________”。 Diagram: Cube net with six squares arranged as follows: Row 1: 学, 海 Row 2: 无, 涯 Row 3: 勤, 思 The characters on the faces are: 学, 海, 无, 涯, 勤, 思 Based on the net, when folded into a cube, the opposite faces are: 学 and 勤 无 and 海 涯 and 思 Answer to the question: The face opposite to "海" is "无".