explain this in simple way like 10 year old child who never learn this in his life past ---**Circuit Description:**
Type: Electrical circuit diagram.
Components:
- Four capacitors: $C_1$, $C_2$, $C_3$, $C_4$. Values: $C_1 = 10$ μF, $C_2 = 30$ μF, $C_3 = 80$ μF, $C_4 = 80$ μF.
- Four resistors: $70 \Omega$, $30 \Omega$ (in series with $C_2$), $30 \Omega$ (in series with $C_4$ and $5 \text{ V}$ source), $100 \Omega$.
- Two voltage sources: $10 \text{ V}$ (positive terminal connected towards the $30 \Omega$ resistor and $C_2$), $5 \text{ V}$ (positive terminal connected towards the $30 \Omega$ resistor and $C_3$).
- Two switches: $S_1$, $S_2$.
- Two labeled points: P, Q.
Connections:
- From a top central point, switch $S_1$ leads to the left and also downwards to point P.
- The wire from $S_1$ going left connects to $C_1$, then to the $70 \Omega$ resistor, then to point Q.
- From point P, switch $S_2$ connects downwards.
- From point Q, a $10 \text{ V}$ voltage source is connected, then a $30 \Omega$ resistor, then $C_2$. The other end of $C_2$ is connected to the wire coming from $S_2$. This forms a branch between Q and the wire from $S_2$.
- From point P, $C_4$ is connected, then a $5 \text{ V}$ voltage source, then a $30 \Omega$ resistor, then $C_3$. The other end of $C_3$ is connected to the $100 \Omega$ resistor, which then connects to point Q. This forms a branch between P and Q.
Initial State:
- No charge on capacitors.
- Keys $S_1$ and $S_2$ are open.
**Problem Description:**
In the circuit shown, initially there is no charge on capacitors and keys S$_1$ and S$_2$ are open. The values of the capacitors are $C_1 = 10$ μF, $C_2 = 30$ μF and $C_3 = C_4 = 80$ μF.
Which of the statement(s) is/are correct?
**Options:**
(A) At time $t = 0$, the key $S_1$ is closed, the instantaneous current in the closed circuit will be 25 mA.
(B) If key $S_1$ is kept closed for long time such that capacitors are fully charged, the voltage across the capacitor $C_1$ will be 4 V.
(C) The key $S_1$ is kept closed for long time such that capacitors are fully charged. Now key $S_2$ is closed, at this time, the instantaneous current across 30 $\Omega$ resistor (between points P and Q) will be 0.2 A (round off to $1^{st}$ decimal place).
(D) If key $S_1$ is kept closed for long time such that capacitors are fully charged, the voltage difference between points P and Q will be 10 V.
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Hi there! Today we're going to learn about electrical circuits by imagining electricity as water flowing through pipes. This makes it much easier to understand! A voltage source is like a water pump that pushes water. A resistor is like a narrow pipe that slows down the flow. A capacitor is like a water tank that can store water. And a switch is like a tap that can turn the flow on or off.