这道题怎样解答？---已知下面一组算式: $\frac{\frac{1}{2}}{1+\frac{1}{2}} = \frac{\frac{1}{2}}{\frac{3}{2}} = \frac{1}{3}$, $\frac{\frac{1}{3}}{1+\frac{1}{3}} = \frac{\frac{1}{3}}{\frac{4}{3}} = \frac{1}{4}$, $\frac{\frac{1}{4}}{1+\frac{1}{4}} = \frac{\frac{1}{4}}{\frac{5}{4}} = \frac{1}{5}$, ... 1. 发现规律。(2分) $\frac{\frac{1}{17}}{1+\frac{1}{17}} = \frac{\frac{1}{(\quad)}}{\frac{(\quad)}{(\quad)}} = \frac{(\quad)}{(\quad)}$， $\frac{\frac{1}{a}}{1+\frac{1}{a}} = \frac{\frac{1}{(\quad)}}{\frac{(\quad)}{(\quad)}} = \frac{(\quad)}{(\quad)}$。 2. 应用规律,计算: $\frac{1}{1+1} + \frac{2}{1+2} + \frac{3}{1+3} + \frac{4}{1+4} + \cdots + \frac{2025}{1+2025} + \frac{\frac{1}{2}}{1+\frac{1}{2}} + \frac{\frac{1}{3}}{1+\frac{1}{3}} + \frac{\frac{1}{4}}{1+\frac{1}{4}} + \cdots + \frac{\frac{1}{2025}}{1+\frac{1}{2025}}$。(3分)