Let's solve this probability problem step by step. We have a bag containing 5 red balls, 3 blue balls, and 2 green balls. We need to find the probability of drawing different colored balls when we randomly select one ball from the bag.
The first step in solving any probability problem is to find the total number of possible outcomes. In this case, we count all the balls in the bag. We have 5 red balls, 3 blue balls, and 2 green balls. Adding these together: 5 plus 3 plus 2 equals 10 total balls.
Now let's calculate the probability of drawing a red ball. The probability formula is the number of favorable outcomes divided by the total number of possible outcomes. For red balls, we have 5 favorable outcomes out of 10 total balls. So P of red equals 5 over 10, which simplifies to 1 over 2, or 0.5, which is 50 percent.
Next, let's calculate the probability of drawing a blue ball. Using the same probability formula, we have 3 blue balls out of 10 total balls. So P of blue equals 3 over 10, which equals 0.3 or 30 percent. This is lower than the probability of drawing a red ball because there are fewer blue balls in the bag.
Finally, let's calculate the probability of drawing a non-green ball. Non-green balls include both red and blue balls. We have 5 red plus 3 blue, which equals 8 non-green balls. So P of non-green equals 8 over 10, which simplifies to 4 over 5, or 0.8, which is 80 percent. To summarize our results: the probability of red is 50 percent, blue is 30 percent, and non-green is 80 percent.