请完成图片中的题目，并给出详细的数学过程，最后总结数学知识点。---**Extracted Content:** **Question A4:** **Question Stem (English):** The diagram shows a regular hexagon with area 48 m². What is the area of the shaded triangle? **Given Information:** Area of the regular hexagon = 48 m². **Question Stem (Chinese):** 图中显示了一个面积为48平方米的正六边形。被遮盖的三角形的面积是多少？ **Diagram Description:** Type: Geometric figure. Description: A regular hexagon is shown. A triangle within the hexagon is shaded. The shaded triangle shares one side with the hexagon and its third vertex is the vertex of the hexagon opposite to that side. **Analysis (not explicitly requested in output format, but derived from the image to understand the shaded triangle):** A regular hexagon can be divided into 6 congruent equilateral triangles by connecting its center to each vertex. Since the total area is 48 m², the area of each of these equilateral triangles is 48 / 6 = 8 m². Let the vertices of the hexagon be V1, V2, V3, V4, V5, V6 in order, and the center be O. If the shaded side is V1-V2, then the shaded triangle has vertices V1, V2, and V4 (the vertex opposite to V1-V2). The diagonal V1-V4 of a regular hexagon passes through the center O. The shaded triangle V1-V2-V4 can be decomposed into two triangles: triangle O-V1-V2 and triangle O-V2-V4. Triangle O-V1-V2 is one of the 6 equilateral triangles, so its area is 8 m². Triangle O-V2-V4 is an isosceles triangle with sides OV2 = OV4 (radii, equal to side length) and angle V2OV4 = 120 degrees. The area of triangle O-V2-V4 is equal to the area of triangle O-V1-V2. Therefore, the area of triangle O-V2-V4 is also 8 m². The area of the shaded triangle V1-V2-V4 is the sum of the areas of triangle O-V1-V2 and triangle O-V2-V4. **Calculated Area of Shaded Triangle (Derived from analysis):** Area = Area(O-V1-V2) + Area(O-V2-V4) = 8 m² + 8 m² = 16 m².