以老师的身份讲解题目，生成视频---94. (2025·全国·专题练习) 如图, PA ⊥ 平面 ABCD, 底面 ABCD 为矩形, AE ⊥ PB 于点 E. 求证: AE ⊥ 平面 PBC ; **Chart/Diagram Description:** * **Type:** 3D Geometric figure representing a pyramid. * **Main Elements:** * **Points:** Labeled points P, A, B, C, D, E, F, G. A, B, C, D form the vertices of the base. P is the apex. E is a point on PB. F and G are points on PC and PD respectively, connected by a line segment FG. * **Lines:** * Solid lines: PB, PC, PD, BC, CD, AE, FG. * Dashed lines: PA, AB, AD, AC (diagonals of the base appear to be implied by the dashed lines from A to C), BD (implied). * Line segment AE is shown originating from A and meeting PB at E, with a right angle symbol at E indicating AE ⊥ PB. * **Shapes:** * Base ABCD is a rectangle. * The figure is a pyramid with apex P and base ABCD. * Triangle PAB, PBC, PCD, PDA are faces of the pyramid. * Plane ABCD is the base plane. * Plane PBC is one of the side faces. * **Relationships:** * PA is perpendicular to the plane ABCD. * ABCD is a rectangle. * AE is perpendicular to PB at point E. * FG is a line segment connecting points F on PC and G on PD. * **Implied relationships from text and figure:** PA ⊥ AB, PA ⊥ AD. Since ABCD is a rectangle, BC || AD and AB || CD, and angles at vertices A, B, C, D are 90 degrees. For example, AB ⊥ BC, AD ⊥ CD. Also, AB ⊥ AD.