How many electrons will move through the cross section of a wire in an 8.0 period of time if the wire is carrying 1.5A of current?
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We need to find how many electrons pass through a wire's cross section in 8 seconds when carrying 1.5 amperes of current. Current is the flow of electric charge, and we can calculate the number of electrons using the relationship between current, charge, and time.
First, we calculate the total charge that flows through the wire using the formula Q equals I times t. Substituting our values: Q equals 1.5 amperes times 8.0 seconds, which gives us 12 coulombs of charge.
Next, we need to know the charge of a single electron. Each electron carries a fundamental charge of 1.602 times 10 to the negative 19 coulombs. To find the number of electrons, we divide the total charge by the charge per electron using the formula n equals Q divided by e.
Now we perform the calculation. Dividing 12 by 1.602 times 10 to the negative 19 gives us 7.49 times 10 to the 19th power electrons. This is our final answer: approximately 7.49 times 10 to the 19 electrons pass through the wire's cross section in 8 seconds.
In summary, we solved this problem using the relationship between current, charge, and the fundamental charge of an electron. With a current of 1.5 amperes flowing for 8 seconds, a total of 12 coulombs of charge passes through the wire. Dividing by the electron charge gives us our final answer: approximately 7.49 times 10 to the 19 electrons.