请替我解答这道题---**Extracted Content:** **Question 24:** **Question Stem:** 如图，点C在线段AB上，AD//EB，AC=BE，AD=BC，CF平分∠DCE．求证：CF⊥DE． **Given Conditions:** * 点C在线段AB上 * AD//EB * AC=BE * AD=BC * CF平分∠DCE **Task:** 求证：CF⊥DE **Geometric Figure Description:** * Type: Geometric diagram showing points, line segments, and angles. * Main Elements: * Points: A, B, C, D, E, F. * Line segment AB, with point C located on it. A, C, B appear to be collinear. * Line segment AD. * Line segment EB. * Line segment CD, forming triangle ACD with AC and AD. * Line segment CE, forming triangle BCE with BC and BE. * Line segment DE, connecting points D and E. * Line segment CF, originating from C and intersecting DE at point F. * AD and EB are marked with double arrowheads, indicating they are parallel. * AC and BE are marked with single tick marks, indicating they are equal in length. * AD and BC are marked with double tick marks, indicating they are equal in length. * Angles ∠DCF and ∠ECF are marked with single arcs, indicating that CF bisects ∠DCE. * Angle ∠CAD is marked with double arcs. * Angle ∠CBE is marked with a single arc. * Small arcs are also present at angles ∠ADC and ∠BEC. * Point F appears to lie on the line segment DE. **Other Relevant Text:** * "24." (Question number) * "如图" (As shown in the figure) * "4/6" (Likely a page number or problem number indicator)