How to solve question no 23---ALGEBRAIC IDENTITIES
Page Number: 49
20. If a + b + c = 0, then a^2/bc + b^2/ca + c^2/ab =
(a) 0
(b) 1
(c) -1
(d) 3
21. If a^(1/3) + b^(1/3) + c^(1/3) = 0, then
(a) a + b + c = 0
(b) (a + b + c)^3 = 27abc
(c) a + b + c = 3abc
(d) a^3 + b^3 + c^3 = 0
22. If a + b + c = 9 and ab + bc + ca = 23, then a^3 + b^3 + c^3 - 3abc =
(a) 108
(b) 207
(c) 669
(d) 729
23. (a^2 - b^2)^3 + (b^2 - c^2)^3 + (c^2 - a^2)^3 / (a - b)^3 + (b - c)^3 + (c - a)^3 =
(a) 3(a + b)(b + c)(c + a)
(b) 3(a - b)(b - c)(c - a)
(c) (a - b)(b - c)(c - a)
(d) (a + b)(b + c)(c + a)
24. The product (a + b)(a - b)(a^2 - ab + b^2)(a^2 + ab + b^2) is equal to
(a) a^6 + b^6
(b) a^6 - b^6
(c) a^3 - b^3
(d) a^3 + b^3
25. The product (x^2 - 1)(x^4 + x^2 + 1) is equal to
(a) x^8 - 1
(b) x^8 + 1
(c) x^6 - 1
(d) x^6 + 1
26. If a/b + b/a = 1, then a^3 + b^3 =
(a) 1
(b) -1
(c) 1/2
(d) 0
27. If 49a^2 - b = (7a + 1/2)(7a - 1/2), then the value of b is
(a) 0
(b) 1/4
(c) 1/√2
(d) 1/2
28. One of the factors of (5x + 1)^2 - (5x - 1)^2 is
(a) 5 + x
(b) 5 - x
(c) 5x - 1
(d) 20x
29. If 9x^2 - b = (3x + 1/2)(3x - 1/2), then the value of b is
(a) [Content not fully visible]
(b) [Content not fully visible]
(c) [Content not fully visible]
(d) [Content not fully visible]
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Let's solve question twenty-three about algebraic identities. We have a complex fraction with cubed terms in both numerator and denominator. The key insight is to use substitution and apply the special identity: if x plus y plus z equals zero, then x cubed plus y cubed plus z cubed equals three x y z. This identity will help us simplify both the numerator and denominator.