帮我生成视频解答本题，题目思路清晰，简洁易懂。---**Title:** 相交线与平行线 (提升拔高) (Intersecting Lines and Parallel Lines (Advanced)) **Question Stem:** 如图，将三角形ABC沿BA方向平移得到三角形EDF (E,D,A,F共线)，∠B=50°，AC与DF相交于点G,GP、EP分别平分∠CGF、∠DEF相交于点P，求∠P的度数。 (As shown in the figure, translate triangle ABC along the direction of BA to obtain triangle EDF (E, D, A, F are collinear), ∠B=50°, AC intersects DF at point G, GP and EP bisect ∠CGF and ∠DEF respectively and intersect at point P, find the measure of ∠P.) **Chart Description:** * **Type:** Geometric figure composed of lines and points, representing two triangles and intersecting lines on a horizontal line. * **Main Elements:** * **Points:** Labeled points are B, D, A, E on a horizontal line. Point C and F are above the horizontal line. Point G is the intersection of AC and DF. Point P is the intersection of GP and EP. Point H is labeled above C. * **Lines:** Triangle ABC formed by segments AB, BC, AC. Triangle EDF formed by segments ED, DF, EF. Segment AC intersects DF at G. Segment GP is drawn from G to P. Segment EP is drawn from E to P. A horizontal line contains points B, D, A, E. * **Angles:** Angle ∠B is marked as 50°. Angle ∠CGF and ∠DEF are relevant due to angle bisectors GP and EP. Angle ∠P is the angle at point P formed by segments GP and EP. * **Labels and Annotations:** Labels for points (B, D, A, E, C, F, G, P, H) and angle value (50° at ∠B). Text labels indicating the problem description. * **Relative Position and Direction:** Triangle ABC is translated to triangle EDF. Points B, D, A, E are collinear on a horizontal line, arranged in that order from left to right. Point C is above the line BDAE. Point F is above the line BDAE. G is the intersection point within the overlapping region of the two triangles' structures. P is another intersection point. **Additional Notes from Problem Description:** * Triangle ABC is translated along the direction of BA to get triangle EDF. * E, D, A, F are stated to be collinear. (Note: The diagram shows B, D, A, E collinear, and F is a vertex of the triangle not on the line BDAE. There might be a discrepancy between the text and the diagram regarding F's collinearity). Assuming the diagram and the translation description (B->D, A->E, C->F) are correct, then B, D, A, E are collinear and F is the translated C. * ∠B = 50°. * AC intersects DF at G. * GP bisects ∠CGF. * EP bisects ∠DEF. * GP and EP intersect at P.