这道题怎么解---**Textual Information:** Question Stem and Conditions: 如图, ∠AOB = ∠COD = 90°, OC平分∠AOB, ∠BOD = 3∠DOE. 试求∠COE的度数. (Translation: As shown in the figure, ∠AOB = ∠COD = 90°, OC bisects ∠AOB, ∠BOD = 3∠DOE. Find the measure of ∠COE.) **Chart/Diagram Description:** * **Type:** Geometric diagram illustrating angles formed by rays emanating from a common vertex. * **Main Elements:** * **Point:** O (vertex of all angles). * **Lines/Rays:** Five rays OA, OB, OC, OD, and OE originate from point O. * **Labels:** Points A, B, C, D, E, and O are labeled on the diagram. * **Relative Position and Direction:** Ray OA points roughly upwards. Ray OB points roughly horizontally to the right. Ray OC is between OA and OB. Ray OE is below OB and above OD. Ray OD is below OE. The rays are arranged in an approximate clockwise order: OA, OC, OB, OE, OD. * **Angles:** The diagram visually represents angles formed by adjacent rays. Specific angle relationships are given in the problem text (∠AOB, ∠COD, ∠BOD, ∠DOE, ∠COE). There are no angle degree values explicitly written on the diagram itself.